Divide 6k2-15-5 by 3k

Based on the question above, I believe that '6k2' would be [tex](6k^2)[/tex]. So by this, I would continue to with the following expression as: [tex]6k^2-15-5\div3k[/tex]

[tex]Simplify: \frac{5}{3} \\ \\ ((6 * (k2)) - 15) - ( \frac{5}{3} *k) \\ \\ ((2*3k^2) - 15) - \frac{5k}{3} \\ \\ \boxed{\boxed{6k^2 - 15 = \frac{6k^2-15}{1} = \frac{(6k^2-15)*3}{3} }} \\ \\ (pull \ out \ like \ terms) \\ \\ 6k^2 - 15 = 3 * (2k^2 - 5) \\ \\ Factoring: 2k^2 - 5 [/tex]

And by this, in order for us to fully understand that this would be true, the following would enable us to understand.

[tex]\Rightarrow \left[\begin{array}{ccc}A+B) * (A-B) =\\ A2 - AB + BA - B2 =\\ A2 - AB + AB - B2 = \\ A2 - B2\end{array}\right] \Leftarrow[/tex]

[tex]\boxed{\bf{ \frac{3*(2k^2-5)*3-(5k)}{3} = \frac{18k^2-5k-45}{3} }}[/tex]

[tex]Factoring : 18k^2 - 5k - 45 \\ \\ \left[\begin{array}{ccc} -810 + 1 = -809 \\ -405 + 2 = -403 \\ -270 + 3 = -267\\ -162 + 5 = -157 \\ -135 + 6 = -129 \\ -90 + 9 = -81 \end{array}\right] [/tex]

[tex](Your \ Answer) : \boxed{\boxed{\bf{ \frac{18k^2-5k-45}{3} }}}[/tex]