The given equation is [tex]\rightarrow 9r+16=\frac{\pi}{5}[/tex]The value of π is 3.14 or [tex]\frac{22}{7}[/tex] that is a fixed Value. [tex]\rightarrow 9r +16=\frac{3.14}{5}\\\\9r+16=0.628\\\\9r=0.628-16\\\\9r=-15.372\\\\r=\frac{-15.372}{9}\\\\r=-1.708[/tex]So, the given equation is Literal ,because variable value is Known.