Q:

Which equation can be rewritten as x + 4 = x2? Assume x > 0A.[tex] \sqrt{x^2}+2+x[/tex]B.[tex] \sqrt{x+2} =x[tex]                                                                                             C.\sqrt{x+4}=x [/tex][/tex]D.[tex] \sqrt{x^2+16}=x [/tex]

Accepted Solution

A:
The answer is C.

If we square both sides of the equation,  we can rid of the exponent on the right side and add a square root to  x + 4