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Answer:Question 1;∴ The y values are 1.49 , 2.98 , 4.47 and 5.96Question 2;∴ The y values are 2.00 , 2.8 , 3.6 and 4.4Question 3;∴ The y values are -9 , -3 , 3 and 9Question 4;∴ y values are[tex] \frac{1}{2}[/tex] , [tex]\frac{3}{4}[/tex] , 1 and [tex]\frac{5}{4}[/tex]Step-by-step explanation:Question 1;Given data,Apples cost [tex]\$1.49[/tex] per pound.[tex]x[/tex]= weight in pound[tex]y[/tex]= Cost in [tex]\$[/tex]Here the relation between [tex]x[/tex] and [tex]y[/tex] comes;[tex]y=x\times 1.49[/tex]   (equation 1)Let, Plug all x value in equation 1;when [tex]x=1[/tex] then [tex]y=1\times 1.49=1.49[/tex],when [tex]x=2[/tex] then [tex]y=2\times 1.49=2.98[/tex],when [tex]x=3[/tex] then [tex]y=3\times 1.49=4.47[/tex],when [tex]x=4[/tex] then [tex]y=4\times 1.49=5.96[/tex],∴ The y values are 1.49 , 2.98 , 4.47 and 5.96Question 2;From question,Initial fees of cab is [tex]\$[/tex]2.00 and Passengers are charged  [tex]\$[/tex]0.80 for every minute.Let,[tex]x[/tex]= Time in minutes[tex]y[/tex]= Amount in [tex]\$[/tex]Here the relation between x and y comes;[tex]y=x\times 0.80 +2.00[/tex]    (equation 2)Let,By plug all x value in equation 2;When [tex]x=0[/tex] then [tex]y=0\times 0.80+2.00=2.00[/tex],When [tex]x=1[/tex] then [tex]y=1\times 0.80+2.00=2.8[/tex],When [tex]x=2[/tex] then  [tex]y=2\times 0.80+2.00=3.6[/tex],When [tex]x=3[/tex] then  [tex]y=3\times 0.80+2.00=4.4[/tex],∴ The y values are 2.00 , 2.8 , 3.6 and 4.4Question 3;Given relation between [tex]x[/tex] and [tex]y[/tex];[tex]y=6\times x +3[/tex]Plug all the values of x in above equation,When [tex]x=-2[/tex] then [tex]y=(6\times -2) +3=-9[/tex],When [tex]x=-1[/tex] then  [tex]y=(6\times --1) +3=-3[/tex],When [tex]x=0[/tex] then [tex]y=(6\times 0) +3=3[/tex],When [tex]x=1[/tex] then [tex]y=(6\times 1) +3=9[/tex],∴ The y values are -9 , -3 , 3 and 9Question 4;Given relation between [tex]x[/tex] and [tex]y[/tex];[tex]y=(\frac{1}{4} \times x)+1[/tex]Plug all the values of x in above equation,When [tex]x=-2[/tex] then [tex]y=(\frac{1}{4} \times -2)+1=\frac{1}{2}[/tex],When [tex]x=-1[/tex] then [tex]y=(\frac{1}{4} \times -1)+1=\frac{3}{4}[/tex],When [tex]x=0[/tex] then [tex]y=(\frac{1}{4} \times 0)+1=1[/tex],When [tex]x=1[/tex] then [tex]y=(\frac{1}{4} \times 1)+1=\frac{5}{4}[/tex],∴ y values are [tex]\frac{1}{2}[/tex] , [tex]\frac{3}{4}[/tex] , 1 and [tex]\frac{5}{4}[/tex]